用 SQL 实现数据的分栏显示
上一篇 / 下一篇 2008-05-29 13:07:16 / 个人分类:Oracle Programming
序号ID NAME ------- --------- ------------- 1 422_01 yuechaotian1 2 422_02 yuechaotian2 3 422_03 yuechaotian3 4 422_04 yuechaotian4 5 422_05 yuechaotian5 6 422_06 yuechaotian6 7 422_07 yuechaotian7 8 422_08 yuechaotian8 9 422_09 yuechaotian9 10 422_10 yuechaotian10 11 422_11 yuechaotian11 12 422_12 yuechaotian12 13 422_13 yuechaotian13 14 422_14 yuechaotian14 15 422_15 yuechaotian15 16 422_16 yuechaotian16 17 422_17 yuechaotian17 18 422_18 yuechaotian18 |
序号 ID NAME 序号 ID
NAMEITPUB个人空间4S@ @g:f |
SQL> create table
test_yct(id, name) as 2 select '422_0'||rownum, 'yuechaotian'||rownum from dual connect by rownum
<10; 表已创建。 SQL> insert into
test_yct 2 select '422_1'||(rownum-1), 'yuechaotian1'||(rownum-1) from dual connect
by rownum <10; 已创建9行。 SQL>
commit; 提交完成。 SQL> select * from
test_yct; ID NAME -----------
---------------- 422_01 yuechaotian1 422_02 yuechaotian2 422_03 yuechaotian3 422_04 yuechaotian4 422_05 yuechaotian5 422_06 yuechaotian6 422_07 yuechaotian7 422_08 yuechaotian8 422_09 yuechaotian9 422_10 yuechaotian10 422_11 yuechaotian11 422_12 yuechaotian12 422_13 yuechaotian13 422_14 yuechaotian14 422_15 yuechaotian15 422_16 yuechaotian16 422_17 yuechaotian17 422_18 yuechaotian18 已选择18行。 |
SQL> SELECT A.N, A.ID,
A.NAME, B.N, B.ID, B.NAME 2 FROM (SELECT N, ID, NAME 3 FROM (SELECT ROWNUM N, ID, NAME FROM
test_yct) 4 WHERE MOD(N, 2) = 1) A, 5 (SELECT N, ID, NAME 6 FROM (SELECT ROWNUM N, ID, NAME FROM
test_yct) 7 WHERE MOD(N, 2) = 0) B 8 WHERE A.N + 1 = B.N; N ID NAME --- -------- ----------------
--- -------
-------------- 1 422_01 yuechaotian1 2 422_02 yuechaotian2 3 422_03 yuechaotian3 4 422_04 yuechaotian4 5 422_05 yuechaotian5 6 422_06 yuechaotian6 7 422_07 yuechaotian7 8 422_08 yuechaotian8 9 422_09 yuechaotian9 10 422_10 yuechaotian10 11 422_11 yuechaotian11 12 422_12 yuechaotian12 13 422_13 yuechaotian13 14 422_14 yuechaotian14 15 422_15 yuechaotian15 16 422_16 yuechaotian16 17 422_17 yuechaotian17 18 422_18 yuechaotian18 已选择9行。 |
SQL> SELECT a.n, A.id,
A.name, b.n, B.id, B.name 2 FROM (SELECT N, id, name 3 FROM (SELECT ROWNUM N, id, name FROM
test_yct) 4 WHERE MOD(FLOOR((N - 1) / 9), 2) = 0) A, 5 (SELECT N, id, name 6 FROM (SELECT ROWNUM N, id, name FROM
test_yct) 7 WHERE MOD(FLOOR((N - 1) / 9), 2) = 1) B 8 WHERE A.N + 9 = B.N; N ID NAME N ID
NAMEITPUB个人空间rWhZ9L-~ `(g 已选择9行。 |
SQL> insert into test_yct values('422_19', 'yuechaotian19');
已创建 1 行。
SQL> commit;
提交完成。
SQL> SELECT a.n, A.id,
A.name, b.n, B.id, B.name 2 FROM (SELECT N, id, name 3 FROM (SELECT ROWNUM N, id, name FROM
test_yct) 4 WHERE MOD(FLOOR((N - 1) / 9), 2) = 0) A, 5 (SELECT N, id, name 6 FROM (SELECT ROWNUM N, id, name FROM
test_yct) 7 WHERE MOD(FLOOR((N - 1) / 9), 2) = 1) B 8 WHERE A.N + 9 = B.N(+); N ID NAME -- ------- ------------- --- ------ ------------- 1 422_01 yuechaotian1 10 422_10 yuechaotian10 2 422_02 yuechaotian2 11 422_11 yuechaotian11 3 422_03 yuechaotian3 12 422_12 yuechaotian12 4 422_04 yuechaotian4 13 422_13 yuechaotian13 5 422_05 yuechaotian5 14 422_14 yuechaotian14 6 422_06 yuechaotian6 15 422_15 yuechaotian15 7 422_07 yuechaotian7 16 422_16 yuechaotian16 8 422_08 yuechaotian8 17 422_17 yuechaotian17 9 422_09 yuechaotian9 18 422_18 yuechaotian18 19 422_19 yuechaotian19 |
SQL> insert into
test_yct 2 select '422_2'||(rownum-1),
'yuechaotian2'||(rownum-1) 3 from dual connect by rownum <10; 已创建9行。 SQL>
commit; 提交完成。 |
SQL> SELECT a.n, A.ID,
A.NAME, b.n, B.ID, B.NAME 2 FROM (SELECT N, ID, NAME 3 FROM (SELECT ROWNUM N, ID, NAME FROM
test_yct) 4 WHERE MOD(FLOOR((N - 1) / 6), 2) = 0) A, 5 (SELECT N, ID, NAME 6 FROM (SELECT ROWNUM N, ID, NAME FROM
test_yct) 7 WHERE MOD(FLOOR((N - 1) / 6), 2)
= 1) B 8 WHERE A.N + 6 = B.N(+) 9 AND a.n <= 6 10 UNION ALL 11 SELECT a.n, A.ID, A.NAME, b.n, B.ID, B.NAME 12 FROM (SELECT N, ID, NAME 13 FROM (SELECT ROWNUM N, ID, NAME FROM
test_yct) 14 WHERE n > 6 * 2 15 AND MOD(FLOOR((N - 6 * 2 -1) / 9), 2) = 0)
A, 16 (SELECT N, ID, NAME 17 FROM (SELECT ROWNUM N, ID, NAME FROM
test_yct) 18 WHERE n > 6 * 2 19 AND MOD(FLOOR((N - 6 * 2 - 1) /
9), 2) = 1) B 20 WHERE A.N + 9 = B.N(+); N ID NAME -- ------- -------------------- --- --- --------
-------- 1 422_01 yuechaotian1 7 422_07 yuechaotian7 2 422_02 yuechaotian2 8 422_08 yuechaotian8 3 422_03 yuechaotian3 9 422_09 yuechaotian9 4 422_04 yuechaotian4 10 422_10 yuechaotian10 5 422_05 yuechaotian5 11 422_11 yuechaotian11 6 422_06 yuechaotian6 12 422_12 yuechaotian12 13 422_13 yuechaotian13 22 422_22 yuechaotian22 14 422_14 yuechaotian14 23 422_23 yuechaotian23 15 422_15 yuechaotian15 24 422_24 yuechaotian24 16 422_16 yuechaotian16 25 422_25 yuechaotian25 17 422_17 yuechaotian17 26 422_26 yuechaotian26 18 422_18 yuechaotian18 27 422_27 yuechaotian27 19 422_19 yuechaotian19 28 422_28 yuechaotian28 20 422_20 yuechaotian20 21 422_21 yuechaotian21 已选择15行。 |
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